WebNov 8, 2013 · Odd and even date in bash Hi All, I'm having the following script: Code: #!/bin/bash date=$ (date +%d) echo $date if [ $ {date%2} -eq 0 ]; then echo 'date is even' else echo 'date is odd' fi but I can not find out why it's not working.Example: Code: WebMar 10, 2024 · First of all, your command is wrong. This will take out only 1,3,5,7,9 to file. odd numbers from 0 to 100 include more than that. Second, you are using useless cat; …
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WebApr 24, 2024 · Bash can filter a list on its own if we can assume no elements contain whitespace: expand the arg list with odd numbers replaced with the empty string using $ {/%/} on the @ array to require a match at the end … WebAug 21, 2024 · Until Loops in Bash. If you are coming from a C/C++ background, you might be looking for a do-while loop but that one doesn't exist in bash. There is another kind of loop that exists in bash. The until loop follows the same syntax as the while loop: until [ condition ]; do [COMMANDS] Done thieves place crossword
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WebFeb 25, 2015 · the loop keeps printing all even numbers between 50 and 100: 50 all odd numbers between 50 and 100: 51 all even numbers between 50 and 100: 52 all odd numbers between 50 and 100: 53 all even numbers between 50 and 100: 54 all odd numbers between 50 and 100: 55 it should be all even numbers between 50 and 100: … WebJun 9, 2024 · So instead of I need to remove odd lines you should be thinking I need to select even lines and then the solution is simply: awk '! (NR%2)' file If you want to save the result to a new file: awk '! (NR%2)' file > newfile or back to the original: awk '! (NR%2)' file > newfile && mv newfile file Share Improve this answer Follow WebApr 1, 2010 · To remove even lines (print odd rows): sed -n ‘p;n’ file Here is what happens under the hood algorithmically: sed: reads in first line -n: suppress output of first line p: prints content of pattern buffer, i.e. the first line, overriding suppressed output n: output is suppressed, so don’t write anything out thieves picnic